Platform 27
Active Member
For reasons that I find utterly terrifying, what I learned in high school physics has refused to ever leave my head. I can't say the same about a great many other things that would be of actual use to me on a daily basis.
Anyway, today marks a milestone, for I have been able to do something useful with that knowledge. Who knows how many decades will elapse until the next occasion?
Using every grade 10's favourite kinematics equations, I managed to derive a general formula that ought to approximate how much time a train adds to its schedule by making a stop, versus running straight through. Drumroll:
where...
tdwell is how long, in seconds, the train remains stopped at the station between the moment it stops and the moment it starts again.
v is the normal continuous running speed of train, in m/s
a is the train's typical rate of acceleration, in m/s^2
b is the train's typical rate of braking, in m/s^2 (will be a negative number)
The formula assumes constant rates of acceleration and braking; I know the real mechanical engineers in the audience will tell me that in the real world you tend to see slight curves in acceleration rates on account of gear ratios and static friction and the like. The other caveat for the formula is that it assumes stations are spaced out far enough that the train in question actually does manage to speed all the way up to v before it begins braking for the next stop. Those aside, it should be a pretty good approximation.
Anyway, today marks a milestone, for I have been able to do something useful with that knowledge. Who knows how many decades will elapse until the next occasion?
Using every grade 10's favourite kinematics equations, I managed to derive a general formula that ought to approximate how much time a train adds to its schedule by making a stop, versus running straight through. Drumroll:
Δtstop = tdwell + (v/2)(1/a – 1/b)
where...
tdwell is how long, in seconds, the train remains stopped at the station between the moment it stops and the moment it starts again.
v is the normal continuous running speed of train, in m/s
a is the train's typical rate of acceleration, in m/s^2
b is the train's typical rate of braking, in m/s^2 (will be a negative number)
The formula assumes constant rates of acceleration and braking; I know the real mechanical engineers in the audience will tell me that in the real world you tend to see slight curves in acceleration rates on account of gear ratios and static friction and the like. The other caveat for the formula is that it assumes stations are spaced out far enough that the train in question actually does manage to speed all the way up to v before it begins braking for the next stop. Those aside, it should be a pretty good approximation.
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